(8x^3y^2/4a^2b^4)^-2

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Solution for (8x^3y^2/4a^2b^4)^-2 equation: 


D( x )

a^2*b^4*((8*x^3*y^2)/4) = 0

a^2*b^4*((8*x^3*y^2)/4) = 0

a^2*b^4*((8*x^3*y^2)/4) = 0

2*a^2*b^4*x^3*y^2 = 0 // : 2*a^2*b^4*y^2

x^3 = 0

x = 0

x in (-oo:0) U (0:+oo)

(a^2*b^4*((8*x^3*y^2)/4))^-2 = 0

1/4*a^-4*b^-8*x^-6*y^-4 = 0 // : 1/4*a^-4*b^-8*y^-4

x^-6 = 0

x należy do O

x belongs to the empty set

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